No, rust is stricter because you need to think a lot more about whether weird edge cases in your unsafe code can potentially cause UB. For ex. If your data structure relies on the Ord interface (which gives you comparison operators and total ordering), and someone implements Ord wrong, you aren’t allowed to commit UB still. In C++ land I’d venture to guess most any developer won’t care - that’s a bug with your code and not the data structure.
It’s also more strict because rusts referencing rules are a lot harder then C’s, since they’re all effectively restrict by default, and just turning a pointer into a reference for a little bit to call a function means that you have to abide by those restrictions now without the help of the compiler.
No, rust is stricter because you need to think a lot more about whether weird edge cases in your unsafe code can potentially cause UB. For ex. If your data structure relies on the
Ordinterface (which gives you comparison operators and total ordering), and someone implements Ord wrong, you aren’t allowed to commit UB still. In C++ land I’d venture to guess most any developer won’t care - that’s a bug with your code and not the data structure.It’s also more strict because rusts referencing rules are a lot harder then C’s, since they’re all effectively
restrictby default, and just turning a pointer into a reference for a little bit to call a function means that you have to abide by those restrictions now without the help of the compiler.